Summary
Chapter 4 of the Class 9 Science NCERT textbook, "Describing Motion Around Us", covers describing motion through displacement, average speed, average velocity, average acceleration, kinematic equations, and uniform circular motion, using position-time and velocity-time graphs.
- Distance vs Displacement — Motion is described using distance and displacement, where displacement is the net change in position with direction and can be zero even when distance travelled is not, as when an athlete runs and returns to the start.
- Speed, Velocity, Acceleration — Average speed is distance over time, average velocity is displacement over time (v_av = s/t), and average acceleration is change in velocity over time, which can occur even at constant speed if direction changes.
- Kinematic Equations — For straight-line motion with constant acceleration, three kinematic equations connect the quantities: v = u + at, s = ut + ½at², and v² = u² + 2as, letting students solve for unknowns of motion.
- Graphs and Circular Motion — Position-time and velocity-time graphs represent motion, where slopes give velocity and acceleration and area under a velocity-time graph gives displacement. In uniform circular motion, changing direction means constant acceleration.
Key points & formulas
- 01Displacement is the net change in position between two instants, requiring both magnitude and direction; it can be zero even when total distance travelled is non-zero (e.g., an athlete who runs and returns to the start)
- 02Average speed equals total distance divided by time interval; average velocity equals displacement divided by time interval (v_av = s/t), with SI unit m s⁻¹
- 03Average acceleration equals change in velocity divided by time interval (a = (v − u)/t), with SI unit m s⁻²; acceleration can exist even when speed is constant, if direction changes
- 04The three kinematic equations for straight-line motion with constant acceleration are: v = u + at, s = ut + ½at², and v² = u² + 2as
- 05On a position-time graph, the slope of the line gives the magnitude of velocity; a straight line indicates constant velocity and a curve indicates changing (accelerated) velocity
- 06In uniform circular motion, an object moves at constant speed in a circular path, but its direction of velocity continuously changes, so it is always accelerating
Frequently asked questions
01What is the difference between distance and displacement in Class 9 Chapter 4?
Distance is the total path length travelled by an object, while displacement is the net change in position between two instants of time. Displacement requires both magnitude and direction. For example, an athlete who runs 100 m forward and 60 m back has travelled 160 m total distance but has a displacement of only 40 m in the forward direction.
02What are the three kinematic equations for uniformly accelerated motion given in Chapter 4?
The three kinematic equations are: (1) v = u + at, (2) s = ut + ½at², and (3) v² = u² + 2as, where u is initial velocity, v is final velocity, a is constant acceleration, t is time interval, and s is displacement. These equations are valid only when acceleration is constant.
03What does the slope of a velocity-time graph represent?
The slope of a straight line on a velocity-time graph represents the average acceleration of the object. If the line is horizontal (zero slope), the velocity is constant and acceleration is zero. A positive slope means the velocity is increasing with constant acceleration, while a negative slope means the velocity is decreasing (deceleration).
04Is the NCERT Class 9 Science Chapter 4 PDF free to download?
Yes, the NCERT Class 9 Science Chapter 4 PDF is free to download on cbseprepmaster.com.
More chapters in Exploration
Read Chapter 4 of Exploration, the Class 9 Science NCERT textbook (2026-27 edition), online for free: the complete chapter as published by NCERT with every diagram, solved example and exercise, with step-by-step solutions, answers and revision notes. Open the NCERT PDF above, or browse all NCERT Class 9 textbooks.
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