Summary
Chapter 13 of the Class 12 Physics NCERT textbook, "Nuclei", covers the structure, composition, and properties of atomic nuclei, explaining nuclear forces, radioactivity, binding energy, and energy release through fission and fusion.
- Inside the nucleus — The chapter examines the nucleus of protons and neutrons, introducing isotopes, isobars, and isotones, and the surprising result that nuclear density stays nearly constant regardless of size.
- Mass, energy, and binding — Einstein's mass-energy relation explains the mass defect: nuclei weigh less than their parts, and this missing mass becomes the binding energy holding nucleons together.
- The nuclear force and radioactivity — A short-range force far stronger than electrical repulsion binds nucleons, while unstable nuclei shed energy through alpha, beta, and gamma decay.
- Fission and fusion — Splitting heavy nuclei (fission) or joining light ones (fusion) releases immense energy — powering reactors and the sun, respectively — millions of times more than chemical reactions.
Key points & formulas
- 01The atomic nucleus contains protons and neutrons (nucleons); its radius follows R = R0A^(1/3) where R0 = 1.2 fm, and nuclear density is approximately 2.3 × 10^17 kg/m^3, independent of mass number A.
- 02Mass defect ΔM = [Zmp + (A−Z)mn] − M leads to nuclear binding energy Eb = ΔMc^2; binding energy per nucleon peaks around 8.75 MeV for A = 56 (iron).
- 03The nuclear force is short-ranged, much stronger than the Coulomb force, and acts equally between neutron-neutron, proton-neutron, and proton-proton pairs.
- 04Radioactivity involves three decay types: alpha decay (helium nucleus emitted), beta decay (electrons or positrons emitted), and gamma decay (high-energy photons emitted).
- 05Nuclear fission of U-235 releases approximately 200 MeV per fissioning nucleus — about a million times more energy than a typical chemical reaction.
- 06Nuclear fusion powers the sun via the proton-proton cycle, in which four hydrogen nuclei fuse into one helium-4 nucleus releasing 26.7 MeV of energy.
Frequently asked questions
01What is nuclear binding energy and how is it calculated?
Nuclear binding energy is the energy required to separate a nucleus into its individual protons and neutrons. It equals the mass defect (ΔM) multiplied by c^2, where ΔM = [Zmp + (A−Z)mn] − M. For example, the oxygen-16 nucleus has a mass defect of 0.13691 u, corresponding to a binding energy of about 127.5 MeV.
02What is the difference between nuclear fission and nuclear fusion?
In fission, a heavy nucleus (such as U-235) splits into two intermediate-mass fragments when struck by a neutron, releasing about 200 MeV per event. In fusion, two light nuclei (such as hydrogen isotopes) combine to form a heavier nucleus, releasing energy because the product is more tightly bound. Fusion powers stars, including the sun.
03How did James Chadwick discover the neutron?
In 1932, Chadwick bombarded beryllium nuclei with alpha particles and observed neutral radiation that could knock protons out of light nuclei. By applying conservation of energy and momentum, he determined these were neutral particles with mass nearly equal to a proton, which he called neutrons. He was awarded the 1935 Nobel Prize in Physics for this discovery.
04Is the NCERT Class 12 Physics Chapter 13 PDF free to download?
Yes, the NCERT Class 12 Physics Part II Chapter 13 (Nuclei) PDF is completely free to download on cbseprepmaster.com.
More chapters in Physics Part II
Read Chapter 13 of Physics Part II, the Class 12 Physics NCERT textbook (2026-27 edition), online for free: the complete chapter as published by NCERT with every diagram, solved example and exercise, with step-by-step solutions, answers and revision notes. Open the NCERT PDF above, or browse all CBSE Class 12 textbooks.
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