Class 12 Mathematics

Chapter 8 — Application of Integrals

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Overview

Summary

Chapter 8 of the Class 12 Maths NCERT textbook, "Application of Integrals", teaches how to use definite integrals to find areas bounded by curves such as circles, ellipses, parabolas and lines — going beyond the area formulas of elementary geometry.

  • Areas as accumulated stripsThe chapter's central idea is to build an area by summing infinitely thin strips: vertical strips integrated as ∫y dx, or horizontal strips as ∫x dy. This lets students measure regions that have no simple geometric formula.
  • Handling curves above and below the axisWhen a curve dips below the x-axis its integral turns negative, so the chapter uses absolute values to keep areas positive — splitting a region into parts where needed, as with the area under y = cos x over a full period.
  • Recovering classic area formulasBy integrating standard curves the chapter re-derives familiar results — the circle's πa² and the ellipse's πab — using symmetry to integrate over one quadrant and scale up, showing calculus underpins the geometry formulas students already know.
Essentials

Key points & formulas

  1. 01Area under a curve y = f(x) between x = a and x = b is given by A = ∫ₐᵇ f(x) dx using vertical strips of width dx.
  2. 02Area bounded by x = g(y), the y-axis, and lines y = c and y = d is given by A = ∫꜀ᵈ g(y) dy using horizontal strips.
  3. 03If a curve lies below the x-axis, the area is taken as the absolute value of the definite integral, since f(x) < 0 gives a negative result.
  4. 04The area enclosed by the circle x² + y² = a² is πa², derived by integrating over one quadrant and multiplying by 4.
  5. 05The area enclosed by the ellipse x²/a² + y²/b² = 1 is πab, obtained similarly using the symmetry of the ellipse.
  6. 06The area bounded by y = cos x between x = 0 and x = 2π equals 4, computed by summing absolute areas of the three regions above and below the x-axis.
Questions

Frequently asked questions

01

What is the main formula used to find the area under a curve in Chapter 8?

The area of the region bounded by the curve y = f(x), the x-axis, and the lines x = a and x = b is given by A = ∫ₐᵇ y dx = ∫ₐᵇ f(x) dx. If the region is bounded by x = g(y) and the y-axis between y = c and y = d, then A = ∫꜀ᵈ g(y) dy.

02

What happens when part of a curve is below the x-axis?

When f(x) < 0 on an interval, the definite integral gives a negative value. The area is taken as the absolute value of the integral. If a curve crosses the x-axis, the total area is the sum of the absolute values of each sub-region, for example A = |A₁| + A₂.

03

What is the area of an ellipse according to NCERT Class 12 Chapter 8?

The area enclosed by the ellipse x²/a² + y²/b² = 1 is πab. This is derived by computing 4 × (1/a) × ∫₀ᵃ b√(a² − x²) dx using the symmetry of the ellipse about both axes, yielding 4b/a × (a²/2) × (π/2) = πab.

04

Is the NCERT Class 12 Maths Chapter 8 PDF free to download?

Yes, the NCERT Class 12 Maths Part II Chapter 8 PDF is completely free to download on cbseprepmaster.com.

Keep learning

More chapters in Mathematics Part II

Read Chapter 8 of Mathematics Part II, the Class 12 Mathematics NCERT textbook (2026-27 edition), online for free: the complete chapter as published by NCERT with every diagram, solved example and exercise, with step-by-step solutions, answers and revision notes. Open the NCERT PDF above, or browse all CBSE Class 12 textbooks.

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