Summary
Chapter 3 of the Class 11 Physics NCERT textbook, "Motion in a Plane", covers motion in two dimensions using vector algebra, including projectile motion and uniform circular motion. Download the free NCERT PDF.
- Vectors as the language of 2D motion — Describing motion in a plane needs vectors, which carry both magnitude and direction. The chapter builds the toolkit—addition, resolution into perpendicular components, and analytical methods—so any plane motion can be handled through its parts.
- Splitting motion into independent axes — A central strategy is treating plane motion as two independent one-dimensional motions along x and y. This reduces complex 2D problems to familiar straight-line kinematics applied separately in each direction.
- Projectile and circular motion — The methods explain projectile motion as a parabolic path from combined horizontal and vertical motion, and uniform circular motion where a centre-directed acceleration continually turns the velocity while keeping speed constant.
Key points & formulas
- 01Vectors have magnitude and direction; scalars have magnitude only. Vector addition follows triangle or parallelogram law, is commutative (A+B=B+A) and associative.
- 02Any vector can be resolved into components along perpendicular axes using unit vectors î and ĵ. Components relate to magnitude and direction angle by Ax = A cos θ, Ay = A sin θ.
- 03Motion in a plane is treated as two independent 1D motions. Using r = r₀ + v₀t + ½at² separately for x and y directions simplifies 2D kinematics.
- 04Projectile motion path is parabolic: y = (tan θ₀)x − gx²/(2v₀² cos² θ₀). Maximum height is hm = (v₀ sin θ₀)²/(2g), reached at time tm = v₀ sin θ₀/g.
- 05Horizontal range of projectile is R = v₀² sin 2θ₀/g, maximum when θ₀ = 45°. Time of flight is Tf = 2v₀ sin θ₀/g.
- 06In uniform circular motion, acceleration (centripetal) always points toward center with magnitude ac = v²/R = ω²R, where ω = v/R is angular speed. Velocity remains tangent to the circle.
Frequently asked questions
01What is the difference between displacement and path length in motion?
Displacement is the straight-line distance from initial to final position, independent of the actual path. Path length is the total distance traveled along the actual trajectory. They are equal only if motion is in a straight line without direction change. In all other cases, path length is greater than or equal to displacement magnitude.
02How do you find the maximum height and time to reach it for a projectile?
Maximum height is hm = (v₀ sin θ₀)²/(2g), where v₀ is initial velocity and θ₀ is launch angle. The time to reach maximum height is tm = v₀ sin θ₀/g. At maximum height, the vertical component of velocity (vy) becomes zero; only horizontal velocity remains.
03Why is the acceleration in uniform circular motion always perpendicular to velocity?
In uniform circular motion, speed is constant but direction continuously changes. Acceleration measures the rate of change of velocity. Since the magnitude is constant, acceleration only changes the direction of velocity, not its magnitude. This requires acceleration perpendicular to velocity (toward center), giving centripetal acceleration ac = v²/R directed radially inward.
04Is the NCERT Class 11 Physics Chapter 3 PDF free to download?
Yes, the NCERT Class 11 Physics Chapter 3 PDF is completely free to download. NCERT textbooks are published by India's National Council of Educational Research and Training as open educational resources for all students.
More chapters in Physics Part I
Read Chapter 3 of Physics Part I, the Class 11 Physics NCERT textbook (2026-27 edition), online for free: the complete chapter as published by NCERT with every diagram, solved example and exercise, with step-by-step solutions, answers and revision notes. Open the NCERT PDF above, or browse all NCERT Class 11 textbooks.
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