Summary
Chapter 7 of the Class 11 Maths NCERT textbook, "Binomial Theorem", provides a formula to expand (a + b)ⁿ for any positive integer n without repeated multiplication, using binomial coefficients ⁿCᵣ from the terms ⁿC₀aⁿ + ⁿC₁aⁿ⁻¹b + … + ⁿCₙbⁿ.
- Expanding powers efficiently — The chapter shows how the Binomial Theorem replaces tedious repeated multiplication with a single expansion formula for any positive integer power, making even high powers of a binomial quick to write out.
- Where the coefficients come from — It connects the expansion's coefficients to Pascal's triangle and to combinations, revealing that the numbers in each row aren't arbitrary but the same ⁿCᵣ counts studied earlier in the course.
- Proof and practical uses — The theorem is justified by mathematical induction and then applied to real tasks — evaluating large powers, handling special cases like (1 + x)ⁿ, and proving divisibility results — showing it as a working tool, not just a formula.
Key points & formulas
- 01Binomial Theorem: (a + b)ⁿ = ΣⁿCₖaⁿ⁻ᵏbᵏ from k=0 to n, where ⁿCᵣ = n!/(r!(n–r)!)
- 02Pascal's triangle and binomial coefficients provide expansion coefficients without multiplication
- 03There are always (n+1) terms in (a + b)ⁿ expansion, with indices of a and b summing to n in each term
- 04Special cases: (x – y)ⁿ uses alternating signs; (1 + x)ⁿ simplifies to ⁿC₀ + ⁿC₁x + ⁿC₂x² + ...
- 05Practical applications include computing large powers (e.g., (98)⁵ = 9039207968) and proving divisibility (e.g., 6ⁿ – 5ⁿ ≡ 1 mod 25)
- 06The theorem simplifies via the summation notation and is proven using mathematical induction
Frequently asked questions
01What is the Binomial Theorem?
The Binomial Theorem provides a formula to expand (a + b)ⁿ for any positive integer n: (a + b)ⁿ = ⁿC₀aⁿ + ⁿC₁aⁿ⁻¹b + ⁿC₂aⁿ⁻²b² + ... + ⁿCₙbⁿ. The coefficients ⁿCᵣ are binomial coefficients calculated as n!/(r!(n–r)!), and the expansion always contains (n+1) terms.
02How are binomial coefficients related to Pascal's triangle?
Binomial coefficients ⁿCᵣ form the rows of Pascal's triangle. Each row corresponds to a power n, where the entries are ⁿC₀, ⁿC₁, ⁿC₂, ..., ⁿCₙ. Each entry is the sum of the two entries above it, creating the triangular pattern: each number equals the sum of the two numbers diagonally above it.
03Is the NCERT Class 11 Maths Chapter 7 PDF free to download?
Yes, the NCERT Class 11 Mathematics Chapter 7 (Binomial Theorem) PDF is available for free download from cbseprepmaster.com.
04How is the Binomial Theorem used to calculate large powers like (98)⁵?
Express the number as a sum or difference of convenient values: 98 = 100 – 2. Then apply the Binomial Theorem to (100 – 2)⁵, which expands to ⁵C₀(100)⁵ – ⁵C₁(100)⁴(2) + ⁵C₂(100)³(2)² – ... The alternating signs come from the (–y)ⁿ case. For (98)⁵, this yields 9039207968, avoiding tedious direct multiplication.
More chapters in Mathematics
Read Chapter 7 of Mathematics — the Class 11 Mathematics NCERT textbook (2026-27 edition) — online for free: the complete chapter as published by NCERT with every diagram, solved example and exercise, with step-by-step solutions, answers and revision notes. Open the NCERT PDF above, or browse all NCERT Class 11 textbooks.
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