Summary
Chapter 7 of the Class 10 Maths NCERT textbook, "Coordinate Geometry", teaches students to find the distance between two points using the Distance Formula and the coordinates of a point dividing a line segment in a given ratio using the Section Formula.
- Geometry through algebra — Coordinate geometry places shapes on a plane with numbered axes so that lengths and positions can be handled with algebra. This bridge lets geometric questions be answered by calculation.
- The Distance Formula — Built from the Pythagoras theorem, the Distance Formula measures the straight-line gap between any two points from their coordinates, and its special case gives the distance of a point from the origin.
- Dividing a segment — The Section Formula pinpoints where a point falls when it splits a segment in a chosen ratio. Setting that ratio to 1:1 recovers the midpoint, the exact centre of the segment.
- Testing collinearity — Distances also reveal whether three points lie on one line: if the two shorter distances add up to the longest, the points are collinear. This supports classifying triangles and quadrilaterals.
Key points & formulas
- 01Distance Formula: the distance between P(x₁,y₁) and Q(x₂,y₂) is √[(x₂–x₁)²+(y₂–y₁)²], derived from the Pythagoras theorem.
- 02Distance of a point P(x,y) from the origin O(0,0) is √(x²+y²).
- 03Section Formula: the point dividing segment AB — where A is (x₁,y₁) and B is (x₂,y₂) — internally in ratio m₁:m₂ has coordinates ((m₁x₂+m₂x₁)/(m₁+m₂), (m₁y₂+m₂y₁)/(m₁+m₂)).
- 04Midpoint Formula (special case of Section Formula with ratio 1:1): midpoint of AB is ((x₁+x₂)/2, (y₁+y₂)/2).
- 05Three points are collinear if the sum of the distances between the two pairs of adjacent points equals the distance between the outermost pair.
- 06Coordinate geometry links algebra and geometry, with applications in physics, engineering, navigation, seismology, and art.
Frequently asked questions
01What is the Distance Formula in Class 10 Maths Chapter 7?
The distance between two points P(x₁,y₁) and Q(x₂,y₂) is PQ = √[(x₂–x₁)²+(y₂–y₁)²]. It is derived by applying the Pythagoras theorem to a right triangle formed by drawing perpendiculars from the two points to the x-axis. For a point P(x,y), its distance from the origin is √(x²+y²).
02What is the Section Formula and when is it used?
The Section Formula gives the coordinates of point P(x,y) that divides the line segment joining A(x₁,y₁) and B(x₂,y₂) internally in the ratio m₁:m₂: x = (m₁x₂+m₂x₁)/(m₁+m₂) and y = (m₁y₂+m₂y₁)/(m₁+m₂). It is used to find a specific point on a segment, determine trisection points, and locate midpoints.
03How do you find the midpoint of a line segment using Chapter 7 formulas?
The midpoint is a special case of the Section Formula where the ratio is 1:1. The midpoint of the segment joining P(x₁,y₁) and Q(x₂,y₂) is ((x₁+x₂)/2, (y₁+y₂)/2). For example, the midpoint of A(6,1) and C(9,4) is (15/2, 5/2), which equals (7.5, 2.5).
04Is the NCERT Class 10 Maths Chapter 7 PDF free to download?
Yes, the NCERT Class 10 Maths Chapter 7 PDF is completely free to download on cbseprepmaster.com.
More chapters in Mathematics
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